The empirical formula of the compound containing 79.8% carbon and 20.2% hydrogen is CH₃
Data obtained from the question
- Carbon = 79.8%
- Hydrogen= 20.2%
- Empirical formula =?
How to determine the empirical formula
Divide by their molar mass
C = 79.8 / 12 = 6.65
H = 20.2 / 1 = 20.2
Divide by the smallest
C = 6.65 / 6.65 = 1
H = 20.2 / 6.65 = 3
Thus, the empirical formula of the compound is CH₃
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