[tex]y=4x-2\\ \\reverse \ the \ x \ and \ y \ to \ get \\ \\ x=4y-2 \\ \\ solve \ for \ the \ new \ y \ to \ get \\ \\4y =x+2 \ \ / :4 \\ \\y=\frac{x}{4} + \frac{2}{4} \\ \\y=\frac{1}{4}x + \frac{1}{2}\\ \\ The \ answer \ is : \\ \\ y=\frac{1}{4}x + \frac{1}{2}[/tex]
