Answer :

[tex]125x^2-100x+20=0\\\\5(25x^2-20x+4)=0\\\\5[(5x)^2-2\cdot5x\cdot2+2^2]=0\\\\5\cdot(5x-2)^2=0\\\\5(5x-2)(5x-2)=0\iff5x-2=0\\\\5x=2\ \ \ \ /:5\\\\x=0.4[/tex]
kate200468
[tex]125x^2-100x+20=0\ /:5\\\\25x^2-20x+4=0\ \ \ \Leftrightarrow\ \ \ (5x)^2-2\cdot5x\cdot2+2^2=0\\\\(5x-2)^2=0\ \ \ \Leftrightarrow\ \ \ 5x-2=0\ \ \ \Leftrightarrow\ \ \ 5x=2\ /:5\ \ \ \Leftrightarrow\ \ \ x=0.4[/tex]

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