Answer :

[tex]AB = \sqrt{(3-6)^{2} + (3-5)^{2}} = \sqrt{13} [/tex]

equation of the circle :

 (x - 3)² + (y - 3)² = 13

(1-3)² + (6-3)² = 13 ⇒ C ∈ circle
(6-3)² + (0-3)² = 18 ≠ 13 ⇒ D ∉ circle
(0-3)² + (3-3)² = 9 ≠ 13  ⇒ E ∉ circle
(3-3)² + (-1-3)² = 16 ≠ 13 ⇒ F ∉ circle
(3-3)² + (6-3)² = 9 ≠ 13 ⇒ G ∉ circle
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