Answer :

[tex](2y+3x)^2=9\iff2y+3x=3\ \vee\ 2y+3x=-3\\\\2y=-3x+3\ \vee\ 2y=-3x-3\\\\y=-\frac{3}{2}x+\frac{3}{2}\ \vee\ y=-\frac{3}{2}x-\frac{3}{2}[/tex]
Ryan2
[tex](2y+3x)^2=9 \\ \\ \sqrt{(2y+3x)^2}=\sqrt9\\ \\ 2y+3x=3\\ \\ 2y=3-3x\\ \\ \boxed{y=\frac{3-3x}{2} }[/tex]

Other Questions