Answer :

ayah1
Lets see:

[tex] \frac{3}{8} + \frac{3}{8} + \frac{3}{8} = \frac{9}{8} = 1\frac{1}{8} [/tex]  which is more than 1, but....

[tex] \frac{3}{8} + \frac{3}{8} = \frac{6}{8} [/tex] 

The answer is 2 

[tex]1= \frac{8}{8} [/tex]

[tex] \frac{8}{8} - \frac{6}{8} = \frac{2}{8} [/tex]



The answer is 2 with a remainder of 2/8 or 1/4 or 0.25

The number of 3/8's that are in 1 is [tex]2\frac{2}{3}[/tex]

From the question,

We are to determine the number of 3/8's that are in 1.

To do this, we will divide 1 by 3/8

The division operation is carried out as shown below

[tex]1 \div \frac{3}{8}[/tex]

This becomes

[tex]1 \times \frac{8}{3}[/tex]

= [tex]\frac{8}{3}[/tex]

= [tex]2\frac{2}{3}[/tex]

Hence, the number of 3/8's that are in 1 is [tex]2\frac{2}{3}[/tex]

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