Bbrainly101
Bbrainly101
10-06-2015
Mathematics
Answered
PLS HELP ASAP :DDDDDDDDDDDDDDDDDDD
Answer :
Hippalectryon
Hippalectryon
10-06-2015
Pythagoras in HBC : [tex]HC=\sqrt{HB^2-BC^2}=\sqrt{20^2-12^2}=16in[/tex]
Pythagoras in HDC : [tex]HD=\sqrt{HC^2-CD^2}=\sqrt{16^2-14^2}\approx\boxed{7.7 in}[/tex]
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