[tex]x(x-6)=4(x+6)\ \ \ |use\ distributive\ property\ a(b+c)=ab+ac\\\\x(x)+x(-6)=4(x)+4(6)\\\\x^2-6x=4x+24\ \ \ \ |subtract\ 4x\ and\ 24\ from\ both\ sides\\\\x^2-10x-24=0\\\\x^2-12x+2x-24=0\\\\x(x-12)+2(x-12)=0\iff(x-12)(x+2)=0\\\\therefore\\\\x-12=0\ or\ x+2=0\\\\Answer:\boxed{x=12\ or\ x=-2}[/tex]