[tex]y=\frac{2}{3}x , \ \ (2,0)\\ \\ m=\frac{2}{3} \\ \\ The \ slope \ of \ lines \ parallel \ is \ the \ same \\ \\ use \ y = mx + b \ and \ the \ point \ (2,0) \ to \ find \ b \\ \\ 0= -\frac{2}{3}\cdot 2+b[/tex]
[tex]0=-\frac{4}{3} +b \\ \\b=-\frac{4}{3} \\ \\y=-\frac{2}{3}x+\frac{4}{3}[/tex]
