[tex]x-2y=5 \\
3x-5y=8 \\ \\
\hbox{solve the first equation for x:} \\
x-2y=5 \ \ \ |+2y \\
x=2y+5 \\ \\
\hbox{substitute 2y+5 for x in the second equation:} \\
3(2y+5)-5y=8 \\
6y+15-5y=8 \\
y+15=8 \ \ \ |-15 \\
y=-7 \\ \\
x=2y+5=2 \times (-7)+5=-14+5=-9 \\ \\
\boxed{(x,y)=(-9,-7)}[/tex]
