The length of the third board is [tex]\frac{7}{16}[/tex].
Given that,
Based on the above information, the calculation is as follows:
[tex]= \frac{14-4-3}{16}[/tex]
[tex]= \frac{7}{16}[/tex]
Here we have determined the common denominators.
Therefore we can conclude that the length of the third board is [tex]\frac{7}{16}[/tex].
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