BlossomFlower
BlossomFlower BlossomFlower
  • 13-04-2015
  • Mathematics
Answered

Please Help! I need an explanation for how to do this... Step-by-step directions would be great!

Simplify. Assume the divisor is not zero.
[tex] \frac{(8x^2y^2 – 4xy^2)}{4xy} [/tex]

Answer :

konrad509
konrad509 konrad509
  • 13-04-2015
[tex]\dfrac{8x^2y^2-4xy^2}{4xy}=\\ \dfrac{8x^2y^2}{4xy}-\dfrac{4xy^2}{4xy}=\\ 2xy-y [/tex]
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