[tex]^{16)}8-1\frac{11}{16}= \frac{128}{16}- \frac{1\cdot16+11}{16}= \frac{128-27}{16}=\bold{ \frac{101}{16}} \\ \\ 1 \frac{3}{5}+1 \frac{1}{4}=^{4)}\frac{1\cdot5+3}{5} +^{5)}\frac{1\cdot4+1}{4}= \frac{32}{20}+ \frac{25}{20}=\bold{ \frac{57}{20}} \\ \\ 5 \frac{1}{4}-1 \frac{1}{8}=^{4)}\frac{5\cdot4+1}{4} -^{2)}\frac{1\cdot8+1}{8}= \frac{84}{16}- \frac{18}{16}= \frac{66}{16}^{(2}=\bold{ \frac{33}{8} } [/tex]
