deb9386 deb9386
  • 06-04-2015
  • Mathematics
Answered

x^2 +8 =0 please show all work

Answer :

konrad509
konrad509 konrad509
  • 06-04-2015
[tex]x^2+8=0\\ x^2=-8\\ x=-\sqrt{-8} \vee x=\sqrt{-8}\\ x=-\sqrt{8\cdot(-1)} \vee x=\sqrt{8\cdot(-1)}\\ x=-\sqrt{8}\cdot\sqrt{-1} \vee x=\sqrt{8}\cdot\sqrt{-1}\\ x=-\sqrt{4}\cdot \sqrt2\cdot i \vee x=\sqrt{4}\cdot \sqrt 2\cdot i\\ x=-2\sqrt{2}i \vee x=2\sqrt{2}i [/tex]
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