Answer :

dln
[tex]Distance\ Formula \\ \sqrt{(y2-y1)^{2}+(x2-x1)^{2}} \\ \\ \sqrt{(-2-(-8))^{2}+(-6-0)^{2}} \\ \\ \sqrt{(6)^{2}+(-6)^{2}} \\ \\ \sqrt{36+36}= \sqrt{72} \\ \\ \sqrt{9*8}= 3\sqrt{8}=3 \sqrt{4*2}=6 \sqrt{2} \\ \\ \boxed{6 \sqrt{2} } [/tex]
yrtemeog123
You can use the distance formula for this. √(x-x)² + (y-y)²

So, √(0 + 6) + (-8 +2)
     =√(6)² + (-6)²
     =√36 + 36
     =√72
     =6√2

So, the distance between those points is 6√2 units.

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