Answer :

[tex]-3\frac{8}{9}\cdot1\frac{1}{2}\\\\\frac{8}{9}\approx1\ therefore\ -3\frac{8}{9}\approx-4\\\\so:-3\frac{8}{9}\cdot1\frac{1}{2}\approx-4\cdot1\frac{1}{2}=-4\cdot(1+\frac{1}{2})=-4(1)-4(\frac{1}{2})=-4-2=\boxed{-6}\\\\Answer:\boxed{A}[/tex]

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