[tex]-\frac{s}{3} > 6\ \ \ |change\ signs\\\\\frac{s}{3} < -6\ \ \ \ |multiply\ both\ sides\ by\ 3\\\\\boxed{s < -18\Rightarrow s\in(-\infty;-18)}\\\\Answer:\boxed{\bxoed{?}}\\\\I\ think,\ correct\ equation\ is:-\frac{s}{3} \geq6\\\\therefore\ answer\ is\ \boxed{\boxed{D.\ s\leq-18}}[/tex]