[tex]g(x) = \frac{1}{3}- \frac{4}{3}x \\\\g(x) = - \frac{4}{3}x +\frac{1}{3}\\\\x=-5\ \ \to\ \ g(x)= - \frac{4}{3}*(-5) +\frac{1}{3}= \frac{20}{3} +\frac{1}{3}=\frac{21}{3}=7\\(-5,7)[/tex]
[tex]x=7\ \ \to\ \ g(x)= - \frac{4}{3}*7 +\frac{1}{3}= - \frac{ 28}{3} +\frac{1}{3}=-\frac{27}{3}=-9\\(7,-9)[/tex]
