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Given a>0 and b>0, which inequality shows the result of solving -ax/b >/ (c-d) for x?

a)x </ ad-ac/b

b)x </ bd-bc/a

c)x >/ bc-bd/a

d)x >/ bd-bc/a

Answer :

konrad509
[tex]-\dfrac{ax}{b}\geq c-d\\ -ax\geq bc-bd\\ x\leq-\dfrac{bc-bd}{a}\\ x\leq\dfrac{bd-bc}{a} [/tex]
facundo3141592

We will see that the solution of the given inequality is:

[tex]\frac{ -(c - d)*b}{a} \ge x[/tex]

How to solve the inequality?

Here we have the inequality:

[tex]-\frac{ax}{b} \ge c - d[/tex]

To solve it, we need to isolate x on one side of the inequality.

First, we can multiply both sides for b:

[tex]-ax \ge (c - d)*b[/tex]

Now we divide both sides by -a, because we are operating with a negative number, we need to change the direction of the greater than or equal to sign, so we will get:

[tex]\frac{ -(c - d)*b}{a} \ge x[/tex]

That is the solution to the given inequality.

If you want to learn more about inequalities:

https://brainly.com/question/18881247

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