f(x)= -1/4(x-1)^2- 3
I dont understand how to figure this question out, i ned the vertex, axis of symmetry, and the zeros.

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25-02-2015
Mathematics

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f(x)= -1/4(x-1)^2- 3
I dont understand how to figure this question out, i ned the vertex, axis of symmetry, and the zeros.

Answer :

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Panoyin Panoyin · Answer 1 · 2015-02-25T21:26:07-05:00

Panoyin Panoyin

25-02-2015

f(x) = -1/4(x - 1)² - 3
f(x) = -1/4(x - 1)(x - 1) - 3
f(x) = -1/4(x² - x - x + 1) - 3
f(x) = -1/4(x² - 2x + 1) - 3
f(x) = -1/4(x²) + 1/4(-2x) + 1/4(1) - 3
f(x) = 1/4x² + 1/2x + 1/4 - 3
f(x) = 1/4x² + 1/2x - 2 3/4

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f(x)= -1/4(x-1)^2- 3 I dont understand how to figure this question out, i ned the vertex, axis of symmetry, and the zeros.

Answer :

Other Questions

f(x)= -1/4(x-1)^2- 3
I dont understand how to figure this question out, i ned the vertex, axis of symmetry, and the zeros.