Answer :

luana
[tex]\frac{1}{3}(x+\frac{2}{3})=\frac{1}{6}(x-4)\ \ \ \ | multiply\ by\ 6\\\\ 2(x+\frac{2}{3})=x-4\\\\ 2x+\frac{4}{3}=x-4\ \ \ | multiply\ by\ 3\\\\ 6x+4=3x-12\ \ \ \ | subtract\ 3x\\\\ 3x+4=-12\ \ \ | subtract\ 4\\\\ 3x=-16 \ \ \ | divide\ by\ 3\\\\ x=-\frac{16}{3}[/tex]
[tex]\frac { 1 }{ 3 } \left( x+\frac { 2 }{ 3 } \right) =\frac { 1 }{ 6 } \left( x-4 \right)[/tex]

[tex]\\ \\ 6\cdot \frac { 1 }{ 3 } \left( x+\frac { 2 }{ 3 } \right) =6\cdot \frac { 1 }{ 6 } \left( x-4 \right)[/tex]

[tex]\\ \\ 2\left( x+\frac { 2 }{ 3 } \right) =x-4\\ \\ 2x+\frac { 4 }{ 3 } =x-4\\ \\ 2x-x=-4-\frac { 4 }{ 3 }[/tex]

[tex]\\ \\ x=-\frac { 12 }{ 3 } -\frac { 4 }{ 3 } \\ \\ x=-\frac { 16 }{ 3 }[/tex]