[tex]-\frac{1}{6}+\frac{2}{3}(9-\frac{3}{4})-\frac{1}{2}=\ \ \ \ \ | make\ common\ denominator\\\\
-\frac{2}{12}+\frac{8}{12}(9-\frac{9}{12})-\frac{6}{12}=\\\\
-\frac{2}{12}+\frac{72}{12}-\frac{72}{144}-\frac{6}{12}=\\\\
-\frac{2}{12}+\frac{72}{12}-\frac{6}{12}-\frac{6}{12}=\\\\
\frac{-2+72-6-6}{12}=\frac{58}{12}\\\\ Solution\ is\ \frac{58}{12}.
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