[tex] \left \{ {{2x+4y=1\ \ | *(-3)} \atop {3x-5y=7\ \ | *2}} \right. \\\\
\left \{ {{-6x-12y=-3} \atop {6x-10y=14}} \right.\\+----\\add\ both\ equations\\\\
-22y=11\ \ \ | divide\ by\ -22\\\\
y=-\frac{1}{2}\\\\
2x=1-4y\ \ | divide\ by\ 2\\\\
x=\frac{1-4y}{2}=\frac{1-4*(-\frac{1}{2})}{2} =\frac{3}{2}[/tex]
