Propane and oxygen react according to the equation: C₃H₈(g) + 5O₂(g) → 3CO₂(g) + 4H₂O(g).
How many grams of water can be produced from the complete combustion of 2.0 moles of C₃H₈(g)?
a. 144.0
b. 82.0
c. 8.0
d. 44.8
e. 22.4
1mole of propane produced 4 moles of water 44g of propane produced 18×4=72g of water 2moles of propane=2×44=88 44:72 88:x 44x=88×72 x=2×72 x=144.0grams option (a)
