30-01-2015
Mathematics

Answered

What are all relative extrema to
f (x)=×^4-32x+4?

Answer :

konrad509 konrad509

30-01-2015

[tex]f(x)=x^4-32x+4\\ f'(x)=4x^3-32\\\\ 4x^3-32=0\\ 4(x^3-8)=0\\ x=2\\\\ f(2)=2^4-32\cdot2+4=16-64+4=-44[/tex]

The only extremum is [tex]-44[/tex] and it's minimum.

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