[tex]2x^2-12x+26=10\ \ \ | subtract\ 10\\\\
2x^2-12x+16=0\ \ \ | divide\ by\ 2\\\\
x^2-6x+8=0\\\\
put\ into\ form:\ (x+d)^2+c=0\\
-6x=2xd\ \ \ | divide\ by\ x\\
d=-3\\
8=d^2+c\\
8=9+c\ \ \ | subtract\ 9\\
c=-1\\\\
After\ completing\ the\ square:\\
(x-3)^2-1=0[/tex]
