We have such inequality
[tex]p- \frac{7}{12}> \frac{3}{10} [/tex] /+[tex] \frac{7}{12} [/tex]
[tex]p> \frac{3}{10}+ \frac{7}{12} \\ p> \frac{3*6}{10*6}+ \frac{7*5}{12*5} \\ p> \frac{18}{60}+ \frac{35}{60} \\ p> \frac{18+35}{60} \\ p> \frac{53}{60} [/tex] - its the answer