[tex]8a^2 + 6a = 5 \\ \\8a^2 + 6a -5 =0\\ \\\Delta = b^{2}-4ac = 6^{2}-4*8* (-5)=36 +160=196\\ \\a_{1}=\frac{-b-\sqrt{\Delta }}{2a} =\frac{-6- \sqrt{196}}{2*8}=\frac{-6- 14}{16}= \frac{-20}{16}=- \frac{5}{4}=-1\frac{1}{4}\\ \\a_{2}=\frac{-b+\sqrt{\Delta }}{2a} =\frac{-6+\sqrt{196}}{2*8}=\frac{-6+14}{16}= \frac{8}{16}= \frac{1}{2} [/tex]
