[tex]4x-8y=0 \\
\underline{-3x+8y=-7} \\
4x-3x=0-7 \\
x=-7 \\ \\
4x-8y=0 \\
4 \times (-7)-8y=0 \\
-28-8y=0 \\
-8y=28 \\
y=\frac{28}{-8} \\
y=-\frac{7}{2} \\ \\
\left \{ {{x=-7} \atop {y=-\frac{7}{2}}} \right. [/tex]
There is one solution to this system of equations. The answer is B.
