Answer :

crisforp
x=0 => y =4 => A(0, 4)∈ Gf;
x = 1 => y = 10/3 => B(1, 10/3)∈ Gf;
Graph tle line AB.
[tex]y=-\frac{2}{3}x+4\\\\for\ x=0\to y=-\frac{2}{3}\cdot0+4=4\to A(0;\ 4)\\\\for\ x=6\to y=-\frac{2}{\not3_1}\cdot\not6^2+4=-4+4=0\to B(6;\ 0)[/tex]
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