zebaali
zebaali
24-11-2014
Mathematics
Answered
(1-sin^2x/cosx)= (sin2x/2sinx)
Answer :
AL2006
AL2006
25-11-2014
Left side:
1-sin²(x) = cos²(x)
1-sin²(x) / cos(x) = cos²(x) / cos(x) =
cos(x)
Right side:
sin(2x) = 2 sin(x) cos(x)
sin(2x) / 2 sin(x) = 2 sin(x) cos(x) / 2 sin(x) =
cos x
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