Answer :

So we have
[tex] \frac{2}{9}j+ \frac{2}{3} [/tex]
We can rewrite it as:
[tex] \frac{2}{3*3}j+ \frac{2}{3}= \frac{2}{3}( \frac{1}{3}j + 1) [/tex] - its our result
Finally we can take 2/3 in front of parenthesis.

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