You find the common denominator for 3/4 and 5/8, which would be 8. Then, the problem turns into 4 5/8 + 1 6/8. You would add them to get the final answer of 6 3/8
[tex]4 \frac{5}{8} +1 \frac{3}{4} [/tex] Put aside the whole numbers [tex] \frac{5}{8} + \frac{3}{4} [/tex] You need to have a common denominator(bottom) [tex] \frac{3}{4} [/tex]×[tex] \frac{2}{2} [/tex]=[tex] \frac{6}{8} [/tex] So [tex] \frac{5}{8} [/tex]+[tex] \frac{6}{8} [/tex]=[tex] \frac{11}{8} [/tex] You then divide the numerator by the denominator 11÷8=1[tex] \frac{3}{8} [/tex] Add that to the original whole numbers [tex]1 \frac{3}{8} +4+1=6 \frac{3}{8} [/tex] There is another way to do this but I decided to do it this way.