31-10-2014
Mathematics

Answered

Which value of b solves the equation? b^-3= = 1/216

Answer :

mariamikayla mariamikayla

31-10-2014

[tex]b^{-3}=\frac{1}{216} \\\\ \frac{1}{b^3}= \frac{1}{216} \\\\ \frac{1}{b^3}=\frac{1}{6^3} \\\\ b^3=6^3 \\\\ \boxed{b=6}[/tex]

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jamiesm jamiesm

31-10-2014

if b^-3=1/216 find the reciprocal (^-1) of each side so it will be b^3=216 and then find the cube root so b=∛216 which is 6

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