Answer:
The correct answer is option B.
Explanation:
Alpha decay: In this process, alpha particles is emitted when a heavier nuclei decays into lighter nuclei. The alpha particle released has a charge of +2 units.
The general alpha decay reaction is given as:
[tex]_Z^A\textrm{X}\rightarrow _{Z-2}^{A-4}\textrm{Y}+_2^4\alpha[/tex]
So, when Pu-239 undergoes alpha decay it gives Uranium-235 and alpha particle.
[tex]_{94}^{239}\textrm{Pu}\rightarrow _{92}^{235}\textrm{U}+_2^4\alpha[/tex]
Hence,the correct answer is option B.