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A dragster in a race accelerated from stop to 60 m/s by the time it reached the finish line. The dragster moved in a straight line and traveled from the starting line to the finish line at 8.0 m/s2. How long did it take the dragster?

Answer :

vf = final velocity
vo = initial velocity
a = acceleration
t = time

use the following equation

vf = vo + at

since vo = 0 m/s (stopped), that term drops out and you're left with . . .

vf = at

(60 m/s) = (8.0 m/s²)t

t = (60 m/s)/(8.0 m/s²) = 7.5 seconds

t = 7.5 seconds

Dragster take 7.5 second.

According to first equation of motion,

V = U + at

t = (V -U)/a

V= final velocity

U=initial velocity

a = acceleration

t = time

given that,

U = 0 m/s (object starts from rest)

V = 60 m/s

a= 8 m/s2

t =?

t = (60 m/s – 0 m/s)/8 m/s2

t = 7.5 s

Thus, we can conclude that, dragster take 7.5 second.

Learn more about equations of motion here:

https://brainly.in/question/17883870

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