Consider the equation [tex] \dfrac{1}{3}(n+1)=\dfrac{1}{6}(3n-5). [/tex]
1 step. Multiply this equation by 6:
[tex] \dfrac{6}{3}(n+1)=\dfrac{6}{6}(3n-5),\\ 2(n+1)=3n-5,\\2n+2=3n-5. [/tex]
2 step. Separate expressions in such way, that variables are in the left side and the numbers are in the right side:
[tex] 2n-3n=-5-2. [/tex]
3 step. Add expressions in both sides:
[tex] n\cdot (2-3)=-(5+2),\\-1\cdot n=-7,\\-n=-7. [/tex]
4 step. Multiply this equaiton by -1:
n=7.
Answer: n=7.
