I arrive home to find that my 50 foot by 40 foot basement has 18 inches of water in it.
- If 1 cubic foot contains 7.48 gallons, how many gallons of water are in my basement?
- If I have a pump that can move 1000 gallons of water per hour, how many hours will it take to remove the water from my basement?

First convert all your measurents into inches 600in, 480in,18in then multiply them to get 5184000 cubic inches, convert cubic inches to gallons and you have 22441US gal lqd divide 22441 by 1000 and it will take you 22.441 hours

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lublana lublana · Answer 2 · 2019-08-18T11:50:39-04:00

Answer:

22.35 hours

Step-by-step explanation:

We given that

Length of basement=50 foot

Breadth of basement =40 foot

Height of water in basement =18 inches

We have to calculate number of hours to remove the water from the basement

We know that 1 inch= 0.083 foot

18 inches =[tex]18\times 0.083[/tex]=1.494 foot

Volume of water in basement =[tex]50\times40\times 1.494[/tex]

Volume of water in basement =2988 cubic foot

We are given that 1 cubic foot =7.48 gallons

2988 cubic foot=[tex]7.48\times2988=22350.24 gallons[/tex]

Volume of water in basement =22350.24 gallons

In one hour, water can remove by pumping=1000 gallons

Time taken to remove 1 gallon of water by pumping =[tex]\frac{1}{1000}[/tex]

Time taken to remove 22350.24 gallons of water by pumping =[tex]\frac{22350.24}{1000}=22.35024[/tex]=22.35 hours

Hence, It will take 22.35 hours to remove the water from my basement .