lekhabodepudi lekhabodepudi
  • 05-10-2014
  • Physics
Answered

At launch the space shuttle weighs 4.5 million pounds. When it is launched from rest, it takes 8.00 s to reach 162km/h , and at the end of the first 1.00 min its speed is 1620km/h .
a)
Assuming
the acceleration is constant during each time interval (but not
necessarily the same in both intervals), what distance does the shuttle
travel during the interval from 8.00 s to 1.00 min?

Answer :

SayMyLastName
SayMyLastName SayMyLastName
  • 05-10-2014
dist = 162*t + A(accelaration)*t^2/2 = 162*52+(((1620-162)/52)*52^2)/2 =162*52+((1620-162)*52)/2=46332kilometres

Answer Link

Other Questions

State a conclusion that seems reasonableA teacher gave all her classes a truefalse test on seven consecutive Mondays Today is Monday Conclusion
The difference between 4632 and 20000 is what number
factorise the expression 3a24ab as far as possible
explain how you could determine which individuals were heterozygous by looking at the gel
based on the theory of evolution in which rock layer would we find the least biodiversity
which is greater 37 or 712
Celia and Ryan are starting a nutrition program Celia currently consume 1200 calories a day and will increase that number by 100 calories each day Ryan currentl
x2 x 6 over x2 7x 10 simplify fully
Nearly 50 of water sources in the United States are believed to be polluted true or false
why are ocean fossils found on top of the rocky mountains