Answer :

luana
[tex]Problem\ 1:\\\\g(h+\frac{2}{3})=1\ \ \ \ \ |:g\\h+\frac{2}{3}=\frac{1}{g}\\h=\frac{1}{g}-\frac{2}{3}\\\\Problem\ 2:\\\\rs-t=us+v\\rs-us=v+t\\s(r-u)=v+t\ \ \ \ |:(r-u)\\s=\frac{v+t}{r-u}[/tex]

Other Questions