Let
x---------> Ramiro's height
y--------> height of the flagpole
z-------> height of the tree
we know that
[tex] z=32\frac{2}{5} \\\\ z=(32*5+2)/5\\\\ z=\frac{162}{5} ft [/tex]
1) Find the height of the flagpole
[tex] y=\frac{5}{9} *\frac{162}{5} \\\\ y=\frac{162}{9} \\\\ y=18 ft [/tex]
2) Find the height of Ramiro
[tex] x=\frac{3}{10} *18\\ \\ x=\frac{54}{10} \\ \\ x=5.4 ft\\ \\ x=5\frac{2}{5} ft [/tex]
therefore
the answer is
The height of Ramiro is [tex] 5\frac{2}{5} ft [/tex]
