lpsneed lpsneed
  • 28-09-2014
  • Mathematics
Answered

how would I solve (-2-2i)(-4-3i)(7+8i)

Answer :

mariamikayla
mariamikayla mariamikayla
  • 28-09-2014
[tex](-2-2i)(-4-3i)(7+8i)= \\\\ =(8+6i+8i+6i^2)(7+8i)=\\\\ =(6i^2+14i+8)(7+8i)= \\\\ =42i^2+98i+56+48i^3+112^2+64i= \\\\ =\boxed{48i^3+154i^2+162i+56}[/tex]
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konrad509
konrad509 konrad509
  • 28-09-2014
[tex](-2-2i)(-4-3i)(7+8i)=\\ (-2-2i)(-28-32i-21i+24)=\\ (-2-2i)(-4-53i)=\\ 8+106i+8i-106=\\ -98+114i [/tex]
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